A 6V battery is connected to the terminals of a three meter long wire of uniform thickness and resistance of 100 Ω Ω . The difference of potential between two points on the wire separated by a distance of 50 cm will be:
Text Solution
Verified by ExpertsThe correct answer is:
C
Total current drawn from the battery
i = 
= 
= 0.06A
Resistance of 50 cm wire is
R' = 
= 
λ ′ 
= 
× 50
so, R' = 
Ω Ω
Hence, the potential difference between two points on the wire separated by a distance λ ′ is
V = iR' = 0.06 × 
= 1V
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